As a result of heating a mole of an ideal gas at constant pressure by `72^(@)C`, a heat flow by an amount 1600 joules takes place. Find the work performed by the gas, the increment of its internal energy, and the value of `gamma`. [Hint:`triangleQ = triangleU + triangleW` or `C_(p) triangleT = C_(v)triangleT + triangleW` or `triangleW = (C_p-C_v)triangleT=RtriangleT] h`

As a result of heating a mole of an ideal gas at constant pressure by

1.	As a result of heating a mole of an ideal gas at constant pressure by `72^(@)C`, a heat flow by an amount 1600 joules takes place. Find the work performed by the gas, the increment of its internal energy, and the value of `gamma`. [Hint:`triangleQ = triangleU + triangleW` or `C_(p) triangleT = C_(v)triangleT + triangleW` or `triangleW = (C_p-C_v)triangleT=RtriangleT] h`
Answer» Correct Answer - `597.6J,0.65^(@)C` `triangleQ = nC_(p)triangleT` `triangleU = nC_(v) triangleT` `triangleW = triangleQ - triangleU = n(C_(p)-C_(v))triangleT` `1(R) triangleT` `=8.3xx72 = 597.6 J` `triangleU = 1600 - 597.6 = 1002.4 J` `r=(C_(p))/(C_(v)) =(1600)/(1002.4)=5/3`

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