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As loop of magnetic moment `M` is placed in the orientation of unstable equilbirum position in a uniform magnetic field `B`. The external work done in rotating it through an angle `theta` isA. `-MB(1-costheta)`B. `-Mbcostheta`C. `Mbcostheta`D. `MB(1-costheta)` |
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Answer» Correct Answer - A `theta_i=180^@, theta_f=180^@-theta` `W=U_f-U_i` `=-Mbcos(180^@-theta)-(-MBcos180^@)` `=Mbcostheta-MB` |
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