As per Bohr model , the minimum energy (in eV) required to remove electron from the ground state of doubly ioinized `Li` alom `(Z = 3)` isA. 1.51B. 13.6C. 40.8D. 122.4

As per Bohr model , the minimum energy (in eV) required to remove elec

1.	As per Bohr model , the minimum energy (in eV) required to remove electron from the ground state of doubly ioinized `Li` alom `(Z = 3)` isA. 1.51B. 13.6C. 40.8D. 122.4
Answer» Correct Answer - B For hydrogen and hydrogen-like atom , `E_(n) = - 13.6 ((z)^(2))/((n)^(2)) eV` Therefore ground state energy of doubly ionized lithium atom `(z = 3, n = 1)` will be `E_(n) = (- 13.6) ((3)^(2))/((2)^(2)) = - 122.4 eV` Therefore , Lonization energy of an electron in ground state of doubly ionized lithium atom will be `122.4 eV`

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As per Bohr model , the minimum energy (in eV) required to remove electron from the ground state of doubly ioinized `Li` alom `(Z = 3)` isA. 1.51B. 13.6C. 40.8D. 122.4

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