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As shown in the figure a rectangular loop of a conducting wire is moving away a constant velocity 'v' in a perpendicular direction from a very long straight conductor carrying a steady current 'I'. When the breadth of the rectangular loop is very small compared to its distance from the straight conductor, how does the e.m.f. 'E' induced in the loop vary with time 't' ? |
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Answer» `E prop (1)/(t^(2))` `E=-(d phi)/(dt)RARR E=-(d(BA))/(dt)` `rArr E=-A(DB)/(dt)=-A(d)/(dt)(mu_(0)I)/(2PI(v t))` `rArr E=-Ai(mu_(0))/(2pi v)(d)/(dt)(t^(-1)) rArr E=Ai (mu_(0))/(2pi v)t^(-2)` `therefore E prop (1)/(t^(2))` |
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