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As the electron in the Bohr orbit is hydrogen atom passes from state `n = 2` to `n = 1` , the `KE (K) and PE (U)` change asA. `K` two-fold, `U`four-foldB. `K` four-fold, `U`two-foldC. `K` four-fold, `U` also four-foldD. `K` two-fold, `U`also four-fold |
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Answer» Correct Answer - C `U = 2E, K=- E` and `E=- (13.6)/(n^(2)) = eV` |
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