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Assertion :lim_(xrarr0)sin(1/x) =0 Reason: If f,g,h :I le Rsuch that g(x) le f(x) le h(x)for all x in a deleted neighbouhood of x_o contained in I and if lim_(xrarr0)g(x)=lim_(xrarrx_o)h(x)=l.Then lim_(xrarrx_o)f(x)=l.[sandwich theorem]

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R is the BEST tool to prove A
R is not enough to prove A
A is not true
both A and R are incorrect

Answer :A


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