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Assume a spherical mammalian cell has a diameter of 27 microns. If a polypeptide chain with alpha helical conformation has to stretch across the cell, how many amino acids should it be comprised of ?A. 180000B. 1800C. 27000D. 12000 |
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Answer» Correct Answer - A No. of amino acid in one term in `alpha` helix = 3.6 Pitch length for `alpha` Helix `= 5.4 A^(@)` `:.` The No. of Amino acid in polypeptide `(3.6)/(5.4xx10^(-10))xx27xx10^(-6)` `=1.8xx10^(4)` Amino acid = 18000 amino acid |
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