Assume that after every budding cycle, the parent organism becomes barren. And the daughter organism produced further gives rise to a new organism. After a period of 78 hours, how many fertile and barren organisms would be left if the initial number of organisms N0 = 2 (Assume that every budding cycle takes 2 hours)?(a) 1 and 2^39-1 respectively(b) 1 and 39 respectively(c) 2 and 78 respectively(d) 2 and 2^40-1 respectivelyThe question was asked during an interview.My query is from Biological Classification topic in chapter Biological Classification of Biology – Class 11

Assume that after every budding cycle, the parent organism becomes bar

1.	Assume that after every budding cycle, the parent organism becomes barren. And the daughter organism produced further gives rise to a new organism. After a period of 78 hours, how many fertile and barren organisms would be left if the initial number of organisms N0 = 2 (Assume that every budding cycle takes 2 hours)?(a) 1 and 2^39-1 respectively(b) 1 and 39 respectively(c) 2 and 78 respectively(d) 2 and 2^40-1 respectivelyThe question was asked during an interview.My query is from Biological Classification topic in chapter Biological Classification of Biology – Class 11
Answer» Correct option is (C) 2 and 78 respectively Best explanation: After one budding cycle, number of fertile and BARREN yeasts are 1 and 1 respectively. After two budding cycles, number of fertile and barren yeasts are 1 and 2 respectively. After n budding cycles, number of fertile and barren yeasts would be 1 and n respectively. Therefore, after 78 hours number of budding cycles = 78/2 = 39 Since, N0 = 2, after 78 hours number of fertile and barren yeasts are 2 and 78 respectively.

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