Assume that float takes 4 bytes, predict the output of following program.#include <stdio.h>int main(){float arr[5] = {12.5, 10.0, 13.5, 90.5, 0.5};float *ptr1 = &arr[0];float *ptr2 = ptr1 + 3;printf("%f ", *ptr2);printf("%d", ptr2 - ptr1);return 0;}(A) 90.5000003(B) 90.50000012(C) 10.00000012(D) 0.5000003