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Assume that the runner in sample question 3 completes the race in 1 inure and 20 seconds. Find her average speed and the magnitude of her average velocity.

Answer»

Solution :Average speed is TOTAL DISTANCE divided by leaped time Since the length of the track is 500 m, the runner's average speed was `(500 m)//(80 s) =6.3 m//s`. However, since her DISPLACEMENT was zero, her average velocity was zero ALSO : `v= Delta s//Delta t = (0 m)//(80s)= 0 m//s`.


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