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Assuming `100%` ionisation, the solution having highest normality is:A. `1 M H_(2)SO_(4)`B. `1 M H_(3)PO_(3)`C. `1 M H_(3)PO_(4)`D. `1 M HNO_(3)` |
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Answer» Correct Answer - C `H_(3)PO_(4)` is tribasic, thus `1 MH_(3)PO_(4)-=3NH_(3)PO_(4) at 100% "ionisation"` |
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