InterviewSolution
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Assuming human pupil to have a radius of 0.25 cm and a comfortable viewing distance of 25 cm, the minimum separation between two objects that human eye can resolve at 500 nm wavelenght is : |
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Answer» `1mu m` `THETA = 1.22 (lambda)/(D)` `therefore ((y)/(25 xx 10^(-2)))` ` = (1.22 xx 500 xx 10^(-9))/(0.25 xx 2 xx 10^(-2))` `rArr y = 30 mu m.`
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