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Assuming the nuclei to be spherical in shape, how does the surface area of a nucleus of mass number A_(1) compare with that of a nucleus of mass number A_(2). |
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Answer» Solution :Since radius of a nucleus `R propA^(1/3)` , HENCE SURFACE area `SpropA^(2/3)` `IMPLIES S_(1)/S_(2)=(A_(1)/A_(2))^(2/3)`. |
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