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Assuming the nuclei to be spherical in shape, how does the surface area of a nucleus of mass number `A_1` compare with that of a nucleus of mass number `A_2`?

Answer» `((A_1)/(A_2))=((R_1)/(R_2))^2=[((A_1)/(A_2))^(1//3)]^2=((A_1)/(A_2))^(2//3)`


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