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Astronunt in space shuttle at 400 km height from Earth surface is observing Earth. If diameter of retina of his eye is 5 mm and wavelength of light is 500 nm, then it will experience the resolution of range of ...... |
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Answer» 0.5 m D=400 km = 400,000 m d=5 mm=`5xx10^(-3) m` `lambda=500 nm=500xx10^(-9)` m `therefore R=1.22xx(500xx10^(-9)xx4xx10^5)/(5xx10^(-3))` `=48.8` m `therefore R=50` m |
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