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At `0^(@)C` , ice and water are in equilibrium and `DeltaS` and `DeltaG` for the conversion of ice to liquid water isA. `0,21.98JK^(-1)mol^(-1)`B. `-ve` , zeroC. `+ve,21.98JKk^(-1)mol^(-1)`D. All of these |
Answer» Correct Answer - D Since the given process is in equilibrium, i.e., `DeltaG=0` `DeltaG=DeltaH-TDeltaS` or, `0=DeltaH-TDeltaS` or `DeltaH=TDeltaS` or, `Delta=(DeltaH)/(T)=(6)/(273)xx10^(3)` `JK^(-1)mol^(-1)=21.98JK^(-1)mol^(-1)` |
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