InterviewSolution
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InterviewSolution
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At `0^(@)C`, ice and water in equilibrium and `Delta H =6.00 kJ mol^(-1)` for the process`H_(2)O (s) rarr H_(2)O(l)`. What will be `Delta S` and `Delta G` for the conversino of ice to liquid water ? |
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Answer» Since the given process inequilibrium , `Delta G = 0` Putting this value in the relationship , `Delta G = DeltaH - T DeltaS ` weget `0= Delta H-T Delta S` or `T DeltaS = DeltaH ` or `Delta S = (DeltaH)/(T)` We are given `DeltaH = 6.0 kJ mol^(-1) = 6000 J mol^(-1) `and `T = 0^(@) C = 273 K` `:. Delta S = ( 6000 J mol^(-1))/( 273K ) = 21.98 J K^(-1) mol^(-1)` |
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