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At 100 K from tata, `N_(2)(g)+3H_(2)(g) rarr2NH_(3)(g)DeltaH^(@)=-123.77"kJmole"^(-1)` `{:("Substance",N_(2),H_(2),NH_(2)),(Cp//R,3.5,3.5,4):}` Calculate the heat of formation of `NH_(3)` to `300 K.` writer your answer, excluding the decimal places.

Answer» Correct Answer - 44


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