At 1x 23. Find the original number if the sum of digit and the number

1.	At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number
Answer» Given, Sum of two DIGITS number =7 Therefore, Ten' digit number = 7-x = 10 (7-x) +x = 70 -10x +x = 70 -9x Now, number obtained by interchanging the digit SO, number = 10x +7-x = 9x +7 According to the question it is given that 27 is added to the ORIGINAL number 70- 9x + 27= 9x+7 70 + 27 - 7 = 9x + 9x 90 = 18x 5= x Now, we have to find the original number By putting the value of x in 70 -9x = 70 - 9×5 = 70 - 45 =25 Hence, the original number is 25

At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number

Answer»

Given,

Sum of two DIGITS number =7

Therefore,

Ten' digit number = 7-x

= 10 (7-x) +x

= 70 -10x +x

= 70 -9x

Now, number obtained by interchanging the digit

SO, number = 10x +7-x

= 9x +7

According to the question

it is given that 27 is added to the ORIGINAL number

70- 9x + 27= 9x+7

70 + 27 - 7 = 9x + 9x

90 = 18x

5= x

Now,

we have to find the original number

By putting the value of x in 70 -9x

= 70 - 9×5

= 70 - 45

=25

Hence, the original number is 25

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At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number​

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At 1x 23. Find the original number if the sum of digit and the number obtained by interchanging thdigits are as follows: (ii)7, 27 more than the original number