1.

At `25^(@)C`, a solution containing `0.2g` of polyisobutylene in `100mL` of benzene develpoed a rise of `2.4mm` at osmotic equilibrium. Calculate the molecular weight of polyisobutylene if the density of solution is `0.88 g// mL`A. `2.39 xx10^(5)g`B. `33.9xx10^(5)g`C. `43.8xx10^(5)g`D. `78.6xx10^(5)g`

Answer» Correct Answer - 1
Height developed `=2.4mm`
Osmotic pressure `=h.d.g.=(2.4)/(10)xx0.88xx981=207.187`dyne`cm^(-2)`
Now `piv=nRTrArr207.187xx100=(0.2)/(m)xx8.314xx10^&(7)xx298" "(R` in erg,V in mL, using CGS system)
`m=2.39xx10^(5)`


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