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At 298 K, the heats of formation fo `C Cl_(4) (g), H_(2)O(g), CO_(2)(g)` and `HCl(g)` are `-25, -57, -94` and `-22` K.cal `mol^(-1)` respectively. The `DeltaH` of the reaction: `C Cl_(4)(g) +2H_(2)O rarr CO_(2) (g) +4HCl(g)`A. `-43` K. calB. `+72` K.calC. `14` K.calD. `-125` K.cal |
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Answer» Correct Answer - A `DeltaH=H_(P)-H_(R)` |
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