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InterviewSolution
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At 300 K the vapour pressure of an ideal solution containing 1 mole of liquid A and 2 moles of liquid B is 500 mm of Hg. The vapour pressure of the solution increases by 25 mm of Hg, if one more mole of B is added to the above ideal solution at 300K. Then the vapour pressure of A in its pure state isA. 300mm of HgB. 400mm of HgC. 500mm of HgD. 600mm of Hg |
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Answer» Correct Answer - A `p_(t)=p_(A)x_(A)+p_(B)x_(B)` `"In lst case, "500=(1)/(3)p_(A)+(2)/(3)p_(B)` `"or "1500=p_(A)+2p_(B)` . . . (i) in llnd case, (when one more mole of B isadded ) `2100=p_(A)+3p_(B)` From Eqs. (i) and (ii) `p_(B)=600mm" Hg and p_(A)=300mm Hg"` |
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