InterviewSolution
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InterviewSolution
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At `460^(@)C, K_(C)=81` for the reaction, `SO_(2)(g)+NO_(2)(g)hArrNO(g)+SO_(3)(g)` A mixture of these gases has the following concentrations of the reactants and products: `[SO_(2)]=0.04M [NO_(2)]=0.04m` `[NO]-0.30m [SO]=0.3m` Is the system at equilibrium? If not, in which direction must the reaction proceed to reach equilibrium. What will be the molar concentrations of the four gases at equilibrium? |
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Answer» Correct Answer - `[SO_(2)]=0.034M;[NO_(2)]=0.034M;[NO]=0.306m;[SO_(3)]=0.306M` `SO_(2)(g)+NO_(2)(g)hArrNO(g)+SO_(3)(g) Q_(c)=((0.3)^(2))/((0.04)^(2))=56.25` `{:(0.04,0.04,0.3,0.3,),(0.04-x,0.04-x,0.3+x,0.3+x,):}` Here, `O_(C)ltK_(C)` hence reaction will proceed in forward direction to reach at state of equilibrium `K_(C)=((0.3+x)^(2))/((0.04-x)^(2))=81` `x=0.006` |
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