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At `500K` , for an isobaric pracess. `DeltaS_(system)=-10(KJ)/(molK)` and `DeltaS_(surr)=12(KJ)/(mol K)` Therefore, `DeltaG` for the entire process isA. `-500KJ//mol`B. `-1000KJ//mol`C. `-600KJ//mol`D. `-1100KJ//mol` |
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Answer» Correct Answer - D `DeltaS_("total")=DeltaS_("system")-(DeltaH)/(T)=2KJ//mol` or `(DeltaH-TDeltaS)/(T)=-2KJ//mol` or `DeltaH-TDeltaS=-2TKJ//mol=-2xx500KJ//mol` `=-1000(KJ)/(mol)` |
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