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At 60% of its usual speed, a train of length L metres crosses platform 240 metreslong in 15 seconds. At its usual speed, the train crosses a pole in 6 seconds. Whatis the value of L (in metres)? |
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Answer» Answer: Answer: Option D. Let usual speed = S m/s. According to the question, 60% of S= (L+240)/15 9S= L+240………… (i) L = 6S …. (II) From (i) & (ii) 9S= 6S+240 3S= 240 S=80 m/s From (ii) L= 6×80 =480 |
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