At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. At 10:15, they are 42.5 km apart. Find the two bicyclists’ rates.

At 9:00 on Saturday morning, two bicyclists heading in opposite direct

1.	At 9:00 on Saturday morning, two bicyclists heading in opposite directions pass each other on a bicycle path.The bicyclist heading north is riding 6 km/hour faster than the bicyclist heading south. At 10:15, they are 42.5 km apart. Find the two bicyclists’ rates.
Answer» HOPE it will help you ..........PLEASE mark me as brainliest...........Step-by-step explanation:LET x=rate of bicyclist HEADING SOUTH x+6=rate of bicyclist heading north distance=travel time*rate travel time=1 hr and 15 min=1.25 hr 1 .25x+1.25(x+6)=42.5 1.25x+1.25x+7.5=42.5 2.5x=35 x=14 x+6=20 rate of bicyclist heading south=14 km/hr rate of bicyclist heading north=20 km/hr