At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1). The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))

At a certain height a body at rest explodes into two equal fragments w

1.	At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1). The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))
Answer» 1s 2s 1.5s 1.75 s Answer :A

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At a certain height a body at rest explodes into two equal fragments with one fragment receiving a horizontal velocity of 10ms^(-1). The time interval after the explosion for which the velocity vectors of the two fragments become perpendicular to each other is (g=10ms^(-2))

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