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At a certain place a magnet makes 30 oscillations per minute. At another place where the magnetic field is double, its time period will beA. `4 sec`B. `2 sec`C. `1/2 sec`D. `sqrt(2) sec` |
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Answer» Correct Answer - D `T=2pisqrt(I/(MB_(H))), :. T_(1)/T_(2)=sqrt((B_(H))_(2)/((B_(H))_(1))) impliesT_(2)=T_(1)sqrt((B_(H))_(1)/((B_(H))_(2)))` Here `n_(1)=30 "oscillation"//"min"=1/2 "oscillation"//"sec"` `:. mu/(4pi).m^(2)/r^(2)=50 gm-wt` `:. T_(2)=2sqrt(B_(H)/(2B_(H)))=2xx1/sqrt(2)=sqrt(2) sec` |
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