1.

At a certain place a small bar magnet completes 30 oscillations per minute. At another place, where the magnetic field is double, its time period will be

Answer»

4 s
2 s
`1/2 s`
`sqrt2`s

Solution :At 1st PLACE `B_1 = B, T_1 = (60)/(30) s = 2s ` .At 2nd place `2B_1 = 2B`
`because (T_1)/(T_2) = SQRT((B_2)/(B_1)) implies T_2 = T_1 xx sqrt((B_1)/(B_2)) = 2 xx sqrt((1)/(2)) = sqrt2 `s


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