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At a certain place, the angle of dip is tan^(-1)(4//5) and angle of declination is 37^(@) The earth's magnetic field has a horizontal component of 0.1 T at that point. A square coil of side 2m is kept in a vertical plane such that its normal points in the true north direction. If the coil is made of 4 rods each of mass 3 kg and the coil is free to rotate about any axis. If the angular acceleration (in rad //s^(2)) of the coil is kxx10^(-2) when a current of 1A passes through it. Find the value of k. |
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Answer» `B_(HN)=0.1sin37^(@)=(4//50)T` `B_(HE)=0.1sin37^(@)=(3//50)T` tau on the COIL due to component of B in N DIRECTION =0 `|VEC(tau)|=|vec(M)xxvec(B)|=1xx2^(2)xx0.1=0.4` Nm `B_(res)=sqrt((3/50)^(2)+(4/50)^(2)=5/50 = 0.1` T `vec(tau)` has direction as shown In its plane, I can be found by `bot` axis theorem `(3xx2^(2)/12+3xx1^(2))xx4=I_(1)=2I` `I=8 kg m^(2)` `alpha=tau/I=(0.4)/8=0.05rad//s^(2)`  
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