1.

At a certain place the horizontl component of earth's magnetic field is sqrt(3) times vertical component. The angle of dip at that place is

Answer»

`75^(@)`
`60^(@)`
`45^(@)`
`30^(@)`

SOLUTION :tan `delta = (B_(V))/(B_(H)) = (1)/(sqrt(3)) rArr delta = tan^(-1) ((1)/(sqrt(3))) = 30^(@)`


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