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At a certain temp. `2HI hArrH_(2) + I_(2)` . Only `50%` HI is dissociated at equilibrium. The equilibrium constant isA. `0.25`B. `1.0`C. `3.0`D. `0.50` |
Answer» Correct Answer - A `underset(50)underset(100)(2HI)hArrunderset(25)underset(0)(H_(2))+underset(25)underset(0)(I_(2))` `([H_(2)][I_(2)])/([HI]^(2)) = (25xx25)/(50xx50) = 0.25` |
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