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At a certain temperature `T`, a compound `AB_(4)(g)` dissociates as `2AB_(4)(g)hArrA_(2)(g)+4B_(2)(g)` with a degree of dissociation `alpha`, which compared to unity. The expressio of `K_(P)` in terms of `alpha` and total pressure `P` is:A. `256 P^(3) alpha^(5)`B. `4Palpha^(2)`C. `8P^(3)alpha^(5)`D. None of these |
Answer» Correct Answer - C `2AB_(4)(g)hArrA_(2)(g)+4B_(2)(g)` `{:(underset(("moles"))(t=0),a,,0,0),(t=t_(Eq),a-aalpha,,(aalpha)/2,2aalpha):}` `K_(p)=(p_(A_(2)).p_(B_(2))^(4))/p_(AB_(4))^(2)` `p_(A_(2))=(aalpha//2)/(a+3/2aalpha).p~~(alphap)/2, p_(B_(2))=(2aalpha)/(a+3/2aalpha).P~~2alphap` `p_(AB_(4))=(a-aalpha)/(a+3/2aalpha).p~~p` `K_(p)=((alphap)/2.(2alphap)^(4))/(p^(2))=8alpha^(5).p^(3)` |
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