At a certain temperature, the first order rate constant `k_(1)` is found to be smaller than the second order rate constant `k_(2)`. If `E_(a)(1)` of the first order reaction is greater than `E_(a)(2)` of the second order reaction, then as temperature is raised:A. `k_(2)` will increase faster than `k_(1)`B. `k_(1)` will increase faster than `k_(2)` but will always remain less than `k_(2)`C. `k_(1)` will increase faster than `k_(2)` and become equal to `k_(2)`.D. `k_(1)` will increase faster than `k_(2)` and become greater than `k_(2)`.

At a certain temperature, the first order rate constant `k_(1)` is fou

1.	At a certain temperature, the first order rate constant `k_(1)` is found to be smaller than the second order rate constant `k_(2)`. If `E_(a)(1)` of the first order reaction is greater than `E_(a)(2)` of the second order reaction, then as temperature is raised:A. `k_(2)` will increase faster than `k_(1)`B. `k_(1)` will increase faster than `k_(2)` but will always remain less than `k_(2)`C. `k_(1)` will increase faster than `k_(2)` and become equal to `k_(2)`.D. `k_(1)` will increase faster than `k_(2)` and become greater than `k_(2)`.
Answer» Correct Answer - A Since `k_(2) gt k_(1)`.

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