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At a constant pressure of `10^(4)Nm^(-2)` , a gas expands by `0.25m^(3)` work done by the gas isA. 2500 JB. 250 JC. 25 JD. 2.5 J |
Answer» Correct Answer - A Given pressure , `p=10^(4)Nm^(-2)` , volume , `V=0.25m^(3)` , work done , W= ? , we know that , `W=pdV=10^(4)xx0.25` =2500 J |
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