1.

At a given time there are 25% undecayed nuclei in a sample. After 10 seconds number of undecayed nuclei reduces to 12-5%. Then mean life of the nuclei will be about:

Answer»

10 sec
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22 sec

Solution :`N/N_(0)=(1/2)^(t//T)`
`N_(1)/N_(0)=1/4 or t_(1)=2T`
`N_(2)=1/8 or t_(2)=3T`
`T=t_(2)-t_(1)=10s"=HALF LIFE"`
`T_("aver.")=(T)/(0.693)=14.43sec`


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