InterviewSolution
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InterviewSolution
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At a height H from the surface of earth, the total energy of a satellite is equal to the potential energy of a body of equal mass at a height 3R from the surface of the earth (R = radius of the earth). The value of H isA. `R`B. `(4R)/(3)`C. `3R`D. `(R)/(3)` |
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Answer» Correct Answer - A We know that the total energy of the satellite is `E=-(1)/(2)(GM_(e)m)/(R)` At a height H from the surface of the earth, the total energy of satellite, `E=-(1)/(2)(GM_(e)m)/(R+H)`....(i) and the potential energy, `U=-(GM_(e)m)/(R+3R)=-(GM_(e)m)/(4R)`....(ii) According to the question, `E=U-(1)/(2).(GM_(e)m)/(R+H)=-(GM_(e)m)/(4R)` `rArr (1)/(2R+2H)=(1)/(4R)rArr2H=4R-2R rArr H=R`. |
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