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At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m^(3)s^(-1). If the turbine generator efficiency is 60%, estimate the electric power available from the plant (g=9.8ms^(-2)). |
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Answer» Solution :Hydroelectric power `=h rho g XX A xx v = h rho g beta` where `beta=Av` is the flow (VOLUME of WATER flowing PER second ACROSS a cross-section). Electric power available `=0.6xx300xx10^(3)xx9.8xx100W` `=176MW` |
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