1.

At a place horizontal component of earth's magnetic field is sqrt(3) times its vertical component. The magnetic dip angle at the place is ...... radian.

Answer»

`0`
`(PI)/(2) "rad"`
`(pi)/(3) "rad"`
`(pi)/(6) "rad"`

Solution :`B_h= SQRT(3) B_v`
but `tan PHI = (B_v)/( B_h)`
`therefore tanphi = (1)/(sqrt(3))`
`therefore phi = tan^(-1) ((1)/(SQRT3)) ""therefore= (pi)/(6) "rad"`


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