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At a place, the horizontal component of earth's magnetic field is B and angle of dip is 60^@. What is the value of horizontal component of the earth's magnetic field at equator? |
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Answer» SOLUTION :The value of horizontal COMPONENT of the earth.s magnetic field at equator is equal to the TOTAL magnetic field `.B_C.` of earth i.e., `(B_H)` equator =` B_E` As at a given place, horizontal component `B_H = B_E cos delta`, where `delta ` is the angle of dip. Hence , we have `B= B_E cos 60^@ = 1/2 B_E impliesB_E = 2B` `implies(B_H)_("equator") = B_E = 2B` |
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