At any instant, the ratio of the amount of radioactive substance is 2: 1. If their half-lives be respectively 12 and 16 hours then after two days, what will be the ratio of the substances ?

At any instant, the ratio of the amount of radioactive substance is 2:

1.	At any instant, the ratio of the amount of radioactive substance is 2: 1. If their half-lives be respectively 12 and 16 hours then after two days, what will be the ratio of the substances ?
Answer» `1:1` `2:1` `1:2` `1:4` Solution :`N_(1)/N_(2)=(2N_(0) E^(-(LN2)/(12) xx48))/(N_(0) e^(-(ln2)/(16) xx 48)) =1 therefore LAMBDA=(ln 2)/(T)`

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At any instant, the ratio of the amount of radioactive substance is 2: 1. If their half-lives be respectively 12 and 16 hours then after two days, what will be the ratio of the substances ?

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