1.

At Assuming complete decomposition of `NH_(3)` and `N(2)H_(4)` `P=0.3 atm, P=2.7 atm` `T=300K, T=200K` `VL, VL` mole `%` of `NH_(3)` in original mixture is (assume both concentration same volume)A. `25%`B. `20%`C. `75%`D. `37.5%`

Answer» Correct Answer - C
Using equation
`PV=nRT`
`n_(1)`= moles of `NH_(3)`
`n_(2)`= moles of `N_(2)H_(4)`
`0.3xxV=(n_(1)+n_(2))xxRxx300`
`2.7xxV=(2n_(1)+3n_(2))xxRxx1200`
`(2n_(1)+3n_(2))/(n_(1)+n_(2))=(9/4)`
`n_(1)/n_(2)=(1/3)`
`n_(1)/n_(2)=75%`


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