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At bandwidth frequency range, the value of the current I is?(a) I=Im/2(b) I=Im^2(c) I=Im(d) I=Im/√2The question was asked in class test.This interesting question is from Bandwidth topic in division Resonance in AC Circuits of Basic Electrical Engineering

Answer»

The correct choice is (d) I=Im/√2

Explanation: At the BANDWIDTH FREQUENCY range, the value of the current is EQUAL to the MAXIMUM value of current divided by √2.



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