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What is the voltage across the inductor when the source voltage is 200V and the Q factor is 10?(a) 100V(b) 20V(c) 2000V(d) 0VThe question was asked in final exam.This is a very interesting question from Quality Factor topic in chapter Resonance in AC Circuits of Basic Electrical Engineering

Answer»

Right OPTION is (c) 2000V

The explanation is: We know that voltage across the capacitor in RESONANCE condition is equal to Q times the source voltage.

Q=VL/VSwhere VL is inductive voltage and VS is source voltage.10=VL/200=>VL = 2000 V.



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