At particle is executing `SHM` with amplitude `A` and has maximum velocity `v_(0)`. Find its speed when it is located at distance of `(A)/(2)` from mean position.

At particle is executing `SHM` with amplitude `A` and has maximum velo

1.	At particle is executing `SHM` with amplitude `A` and has maximum velocity `v_(0)`. Find its speed when it is located at distance of `(A)/(2)` from mean position.
Answer» Correct Answer - `(sqrt(3)v_(0))/(2)` `v_(0) = Aomega rArr omega = (v_(0))/(A)` `v^(2) = omega^(2) (A^(2) - x^(2))` `v^(2) = ((v_(0))/(A))^(2) (A^(2) - (A^(2))/(2^(2)))` `v^(2) = v_(0)^(2) (3)/(4), v = (sqrt(3t))/(2)v_(0)`

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At particle is executing `SHM` with amplitude `A` and has maximum velocity `v_(0)`. Find its speed when it is located at distance of `(A)/(2)` from mean position.

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