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                                    At pH=2, EQuinhydrone will be (EQuinhydrone=1.30 V) [Assume that the concentration of hydroquinone and quinone is 1 M]QH2→Q+2H++2e−, where QH2 and Q stand for hydroquinone and quinone respectively. (Given, 2.303RTF=0.06) | 
                            
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Answer» At pH=2, EQuinhydrone will be (EQuinhydrone=1.30 V) [Assume that the concentration of hydroquinone and quinone is 1 M] QH2→Q+2H++2e−, where QH2 and Q stand for hydroquinone and quinone respectively. (Given, 2.303RTF=0.06)  | 
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