1.

At pH=2, EQuinhydrone will be (EQuinhydrone=1.30 V) [Assume that the concentration of hydroquinone and quinone is 1 M]QH2→Q+2H++2e−, where QH2 and Q stand for hydroquinone and quinone respectively. (Given, 2.303RTF=0.06)

Answer» At pH=2, EQuinhydrone will be (EQuinhydrone=1.30 V) [Assume that the concentration of hydroquinone and quinone is 1 M]

QH2Q+2H++2e, where QH2 and Q stand for hydroquinone and quinone respectively. (Given, 2.303RTF=0.06)


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