1.

At sea level, a `N_(2)`, molecule in air has an average translational `KE=6.2xxx10^(-21)J`. Its mass is `4.7xx10^(-26)kg.` If the molecule shoots up straight without any resistance, it will risw to a height ofA. `135km`B. `13.5km`C. `1.35 km`D. `1350 km`

Answer» Correct Answer - B
Here,`K.E.=6.2xx10^(21)J, m=4.7xx10^(-26)kg`
As `KE` of molecule will get converted into its `PE` as the water level rise.
`:. PE=6.2 xx10^(21)J=mgh`
or `h=(6.2xx10^(-21))/(mg)=(6.2xx10^(-21))/(4.7xx10^(-26)xx98)`
`~~13.5xx10^(3)m =13.5km`


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