1.

At t lt 0, the capacitor is charged and the switch is opened.At t = 0 the switch is closed.The shortest time T at which the charge on the capacitor will be zero is given by:

Answer»

`PI sqrtLC`
`(3)/(2) pi SQRT(LC)`
`(pi)/(2) sqrtLC`
`2pi sqrt LC`

Solution :The time period of LC oscillations `T = 2 pi sqrt(LC)`
The time at which charge on the capactior will be ZERO is `(T)/(4)` . So, `t = (pi)/(2) sqrt(LC)`


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