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At temperature above 85 K, decarboxylation of acetic acid becomes a spontaneous process under standard state conditions. What is the standard entropy change (in J/K-mol) of the reaction. `CH_(3)COOH (aq) rarr CH_(4)(g) +CO_(2)(g)` `{:("Given :",DeltaH_(f)^(@)[CH_(3)COOH (aq)],=-484" kJ/mole"),(,DeltaH_(f)^(@)[CO_(2)(g)],=-392" kJ/mole"),(,DeltaH_(f)^(@)[CH_(4)(g)],=-75" kJ/mole"):}` |
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Answer» Correct Answer - 200 J/K mole `DeltaS=(DeltaH)/(T) =(-392-75-(-484))/(85) =200 J//K` mole |
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