1.

At the surface of the Earth, an object of mass m has weight w. If this object is transported to an altitude that's twice the radius of the Earth, then, at the new location,

Answer»

its mass is `(m)/(2)` and its weight is `(w)/(2)`
its mass is m and its weight is `(w)/(2)`
its mass is `(m)/(2)` and its weight is `(w)/(4)`
its mass is m and its weight is `(w)/(9)`

SOLUTION :Along the Earth's surface (r= R), the gravitational pull is APPROXIMATELY `g=10 m//s^(2)`. When the satellite is at an altiude of twice the Earth's radius, the radius is ACTUALLY equal to 3 R (accounting for the radius from the center of the Earth to the surface). Since the radius is three times away, the inverse square law results in a gravitational acceleration that is `1//9` TH the normal gravitational pull oe Earth at the surface (r= R). This is (d).


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